Simplified Reinforced Concrete Design 2015 Nscp Pdf Link Page

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ρ=0.85fc′fy(1−1−2Rn0.85fc′)rho equals the fraction with numerator 0.85 f sub c prime and denominator f sub y end-fraction open paren 1 minus the square root of 1 minus the fraction with numerator 2 cap R sub n and denominator 0.85 f sub c prime end-fraction end-root close paren Step 5: Verify Minimum Reinforcement ( As,mincap A sub s comma m i n end-sub